[{"data":1,"prerenderedAt":186},["ShallowReactive",2],{"topic-page:\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox\u002Foxidation-reduction-and-electron-transfer":3},{"topic":4,"category":147,"seo":152,"breadcrumbs":157,"prerequisites":164,"nextTopics":176,"relatedTopics":185},{"id":5,"slug":6,"title":7,"summary":8,"canonicalPath":9,"categoryPath":10,"difficulty":11,"targetAudience":12,"estimatedMinutes":13,"generatedAt":14,"publishedAt":14,"updatedAt":14,"reviewStatus":15,"tags":16,"expectedKnowledge":22,"learningGoal":26,"blocks":27},"high-school-basic-chemistry-acid-base-and-redox-oxidation-reduction-and-electron-transfer","oxidation-reduction-and-electron-transfer","酸化・還元と電子の授受","酸化・還元の定義を酸素や水素の授受から電子の授受へ広げ、二つが常に同時に起こることを学びます。","\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox\u002Foxidation-reduction-and-electron-transfer","\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox","beginner","student_high",5,"2026-07-28","ai_generated",[17,18,19,20,21],"化学基礎","酸化","還元","電子授受","半反応式",[23,24,25],"イオンと電荷","化学反応式","中学理科の酸化と還元","酸化と還元を酸素・水素・電子の授受で判定し、電子を失う反応と受け取る反応が同時に起こる理由を説明できるようになる。",[28,34,44,69,75,93,102,108,114,128,137],{"id":29,"type":30,"title":31,"subtitle":32,"shortDefinition":33},"hero","HeroBlock","電子は失う側と受け取る側を結ぶ","酸化と還元は必ず同時に起こる","電子を失う変化が酸化、電子を受け取る変化が還元です。電子が反応中に消えたり生まれたりしないため、二つは同時に起こります。",{"id":35,"type":36,"term":37,"definition":38,"plainExplanation":39,"keywords":40},"definition","DefinitionBlock","酸化と還元","酸化は電子を失う変化、還元は電子を受け取る変化です。","中学校で学んだ酸素を受け取る酸化、酸素を失う還元は、電子授受の見方へ広げられます。水素については、水素を失う変化を酸化、受け取る変化を還元と見ることがあります。どの見方でも一つの反応内で酸化と還元を対応させます。",[41,42,43],"電子を失う酸化","電子を受け取る還元","同時に起こる",{"id":45,"type":46,"title":47,"lead":48,"formulas":49,"strategy":68},"formula","FormulaBlock","電子授受を分けて書く","亜鉛と銅イオンの反応を二つの半反応へ分けます。",[50,59],{"label":51,"expression":52,"meaning":53,"symbols":54,"tip":58},"亜鉛の酸化","Zn → Zn²⁺ + 2e⁻","Zn原子は電子2個を失ってZn²⁺になります。",[55],{"symbol":56,"meaning":57},"e⁻","電子","右辺に電子があれば、その粒子は電子を失っています。",{"label":60,"expression":61,"meaning":62,"symbols":63,"tip":67},"銅イオンの還元","Cu²⁺ + 2e⁻ → Cu","Cu²⁺は電子2個を受け取ってCu原子になります。",[64],{"symbol":65,"meaning":66},"2e⁻","受け取る電子2個","左辺に電子があれば、その粒子は電子を受け取っています。","粒子の電荷変化を見て半反応を書き、失う電子数と受け取る電子数が一致するか確認します。",{"id":70,"type":71,"src":72,"alt":73,"caption":74},"diagram","DiagramBlock","\u002Fassets\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox\u002Foxidation-reduction-and-electron-transfer\u002Felectron-transfer.svg","亜鉛原子から銅イオンへ電子2個が移り、亜鉛イオンと銅原子になる図","Znから出た電子2個をCu²⁺が受け取ります。酸化側と還元側を粒子名、電子記号、方向矢印で結び、電子数の一致を示します。",{"id":76,"type":77,"columns":78,"rows":80,"summary":92},"compare","CompareBlock",[79,18,19],"見方",[81,84,86,88],[57,82,83],"失う","受け取る",[85,83,82],"酸素",[87,82,83],"水素",[89,90,91],"同一反応","還元と同時","酸化と同時","電子授受は酸素を含まない反応にも使える、より広い判定法です。",{"id":94,"type":95,"steps":96,"title":101},"steps","StepBlock",[97,98,99,100],"反応前後で同じ元素を含む粒子を対応させる","電荷変化から失った、または受け取った電子数を求める","電子を右辺へ書く側を酸化、左辺へ書く側を還元とする","両半反応の電子数が等しく、全体で消去できるか確認する","電子で判定する手順",{"id":103,"type":104,"scenario":105,"explanation":106,"result":107},"example","ExampleBlock","CuO(s)+H₂(g)→Cu(s)+H₂O(l)を、酸素と水素の授受から判定する。","CuOは酸素を失ってCuになるため還元されています。H₂は酸素を受け取ってH₂Oになるため酸化されています。別の見方では、H₂は水素を失う側ではなく、ここでは酸素を受け取る判定を使います。一つの反応で両者が同時です。","CuOが還元、H₂が酸化です。次の酸化数を使うと、電子授受としても統一して判定できます。",{"id":109,"type":110,"warningTitle":111,"message":112,"severity":109,"action":113},"warning","WarningBlock","酸化を酸素との反応だけに限定しない","Zn+Cu²⁺→Zn²⁺+Cuのように酸素を含まない反応も酸化還元です。また電子を失う側だけを見て終わらず、同じ電子数を受け取る側を必ず探します。","二つの半反応を書き、電子が全体式で消えることを検算しましょう。",{"id":115,"type":116,"title":117,"questions":118},"quiz","QuizBlock","確認テスト",[119],{"question":120,"choices":121,"answerIndex":123,"choiceExplanations":124},"Fe²⁺ → Fe³⁺ + e⁻という変化の説明として正しいものはどれですか。",[41,42,122],"H⁺を受け取る中和",0,[125,126,127],"正解です。電子が右辺にあり、Fe²⁺は電子1個を失っています。","還元なら電子は反応物側にあり、粒子が受け取ります。","この式にはH⁺やOH⁻がなく、電子授受を判定する場面です。",{"id":129,"type":130,"title":131,"points":132},"summary","SummaryBlock","まとめ",[133,134,135,136],"電子を失う変化が酸化、受け取る変化が還元","酸素・水素の授受も電子授受の見方へ広げられる","酸化と還元は同じ数の電子を介して同時に起こる","半反応式は原子数、電荷、電子数で検算する",{"id":138,"type":139,"title":140,"nextTopics":141,"relatedKeywords":143},"next-action","NextActionBlock","次は酸化数で反応全体を読む",[142],"high-school-basic-chemistry-acid-base-and-redox-oxidation-numbers",[144,145,146],"酸化数","増加","減少",{"path":10,"title":148,"description":149,"parentPath":150,"accentToken":151},"酸・塩基と酸化還元","酸・塩基と中和、pH、酸化還元、金属のイオン化傾向や電池の入口を整理していくカテゴリです。","\u002Fhigh-school\u002Fbasic-chemistry","signal-blue",{"title":153,"description":154,"canonicalUrl":155,"ogImage":156},"酸化・還元と電子の授受 | 化学基礎","高校化学基礎の酸化還元を、酸素・水素の授受から電子を失う酸化、受け取る還元へ広げます。","https:\u002F\u002Fzeqnilo.com\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox\u002Foxidation-reduction-and-electron-transfer","https:\u002F\u002Fzeqnilo.com\u002Fassets\u002Fsite\u002Fdefault-og.svg",[158,161,162,163],{"title":159,"path":160},"高校","\u002Fhigh-school",{"title":17,"path":150},{"title":148,"path":10},{"title":7,"path":9},[165],{"id":166,"title":167,"summary":168,"canonicalPath":169,"categoryPath":10,"categoryTitle":148,"difficulty":11,"targetAudience":12,"estimatedMinutes":170,"publishedAt":14,"updatedAt":14,"reviewStatus":15,"tags":171},"high-school-basic-chemistry-acid-base-and-redox-salts-and-solution-properties","塩と水溶液の性質","中和で生じる塩を構成イオンへ分け、元の酸・塩基の強弱と水との反応から水溶液の性質を定性的に考えます。","\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox\u002Fsalts-and-solution-properties",6,[17,172,173,174,175],"塩","加水分解","液性","中和",[177],{"id":142,"title":178,"summary":179,"canonicalPath":180,"categoryPath":10,"categoryTitle":148,"difficulty":11,"targetAudience":12,"estimatedMinutes":170,"publishedAt":14,"updatedAt":14,"reviewStatus":15,"tags":181},"酸化数の決め方","単体、単原子イオン、化合物の基本規則から酸化数を決め、反応前後の増減で酸化・還元を判定します。","\u002Fhigh-school\u002Fbasic-chemistry\u002Facid-base-and-redox\u002Foxidation-numbers",[17,144,182,183,184],"酸化還元","電荷","判定",[],1785565316287]